Search Results
Matches 1 to 3 of 3 for Last Name equals ÜBERFUHR AND Tree equals Suedpfalz
# | Last Name, Given Name(s) ![]() |
Person ID | Born/Christened ![]() |
Location |
---|---|---|---|---|
1 | ![]() | I64249 | b. 25 Nov 1872 | Nixdorf, Österreich ![]() |
2 | ![]() | I64251 | b. 11 Apr 1898 | Brooklyn, Kings County, New York, USA ![]() |
3 | ![]() | I64250 | b. 6 Jul 1891 | Oberschlettenbach, Pfalz, Bayern ![]() |