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Matches 1 to 2 of 2 for Last Name equals PANKOW AND Tree equals Suedpfalz
# | Last Name, Given Name(s) ![]() |
Person ID | Born/Christened ![]() |
Location |
---|---|---|---|---|
1 | ![]() | I256319 | ||
2 | ![]() | I113693 | b. 30 Aug 1911 | North Dakota, USA ![]() |
Matches 1 to 2 of 2 for Last Name equals PANKOW AND Tree equals Suedpfalz
# | Last Name, Given Name(s) ![]() |
Person ID | Born/Christened ![]() |
Location |
---|---|---|---|---|
1 | ![]() | I256319 | ||
2 | ![]() | I113693 | b. 30 Aug 1911 | North Dakota, USA ![]() |