Search Results
Matches 1 to 17 of 17 for Last Name equals BUCKLEY AND Tree equals Suedpfalz
# | Last Name, Given Name(s) ![]() |
Person ID | Born/Christened ![]() |
Location |
---|---|---|---|---|
1 | ![]() | I393436 | ||
2 | ![]() | I393437 | ||
3 | ![]() | I393438 | ||
4 | ![]() | I52466 | ||
5 | ![]() | I427624 | b. 27 Dec 1799 | Virginia, USA ![]() |
6 | ![]() | I193440 | b. 8 Feb 1937 | Colorado, USA ![]() |
7 | ![]() | I52467 | ||
8 | ![]() | I112445 | b. 18 Feb 1923 | Denver, Denver County, Colorado, USA ![]() |
9 | ![]() | I393432 | ||
10 | ![]() | I393433 | ||
11 | ![]() | I251670 | ||
12 | ![]() | I274036 | ||
13 | ![]() | I393434 | b. 11 Nov 1917 | |
14 | ![]() | I112442 | b. 1901 | Nebraska, USA ![]() |
15 | ![]() | I443186 | b. 7 Mar 1843 | Neave, Bracken County, Kentucky, USA ![]() |
16 | ![]() | I393431 | b. 13 May 1883 | Mandan, Morton County, North Dakota, USA ![]() |
17 | ![]() | I52465 | b. 1903 | USA ![]() |