Search Results
Matches 1 to 3 of 3 for Last Name equals BRINKMANN AND Tree equals Suedpfalz
# | Last Name, Given Name(s) ![]() |
Person ID | Born/Christened ![]() |
Location |
---|---|---|---|---|
1 | ![]() | I407490 | ||
2 | ![]() | I407491 | ||
3 | ![]() | I166789 | b. 1 Mar 1909 | Ferdinand, Dubois County, Indiana, USA ![]() |