Search Results
Matches 1 to 7 of 7 for Last Name equals BRINKERHOFF AND Tree equals Suedpfalz
# | Last Name, Given Name(s) ![]() |
Person ID | Born/Christened ![]() |
Location |
---|---|---|---|---|
1 | ![]() | I308781 | b. 10 Jan 1899 | Missouri, USA ![]() |
2 | ![]() | I308780 | b. 2 Aug 1900 | Missouri, USA ![]() |
3 | ![]() | I308784 | b. 10 Feb 1923 | Chicago, Cook County, Illinois, USA ![]() |
4 | ![]() | I308779 | b. 31 May 1870 | Kansas, USA ![]() |
5 | ![]() | I308782 | b. 9 Nov 1906 | Alamosa, Alamosa County, Colorado, USA ![]() |
6 | ![]() | I308785 | b. 20 Jun 1925 | Buffalo, Erie County, New York, USA ![]() |
7 | ![]() | I308786 | b. 18 Jun 1928 | Buffalo, Erie County, New York, USA ![]() |