Search Results
Matches 1 to 5 of 5 for First Name contains PANSY AND Tree equals Suedpfalz
# | Last Name, Given Name(s) ![]() |
Person ID | Born/Christened ![]() |
Location |
---|---|---|---|---|
1 | ![]() | I171867 | b. 1887 | Lafayette, Tippecanoe County, Indiana, USA ![]() |
2 | ![]() | I194039 | b. 18 Jul 1898 | New South Wales, Australia ![]() |
3 | ![]() | I127550 | b. 24 Jul 1911 | Xenia, Greene County, Ohio, USA ![]() |
4 | ![]() | I102108 | b. 12 Feb 1903 | Indiana, USA ![]() |
5 | ![]() | I467835 |