Search Results
Matches 1 to 10 of 10 for First Name contains ALFORD AND Tree equals Suedpfalz
# | Last Name, Given Name(s) ![]() |
Person ID | Born/Christened ![]() |
Location |
---|---|---|---|---|
1 | ![]() | I126031 | b. 25 May 1889 | Lyons, Wayne County, New York, USA ![]() |
2 | ![]() | I42388 | b. 27 Oct 1908 | Gilmans, Jefferson County, Kentucky, USA ![]() |
3 | ![]() | I40537 | b. 22 Oct 1927 | Crestwood, Oldham County, Kentucky, USA ![]() |
4 | ![]() | I370916 | b. 9 May 1884 | Brazoria, Brazoria County, Texas, USA ![]() |
5 | ![]() | I370919 | b. 7 Feb 1920 | Louisiana, USA ![]() |
6 | ![]() | I261553 | b. 9 Sep 1892 | Ohio, USA ![]() |
7 | ![]() | I181593 | b. 22 Jul 1936 | Paris, Logan County, Arkansas, USA ![]() |
8 | ![]() | I374494 | ||
9 | ![]() | I264064 | b. 24 Dec 1916 | Brown County, Ohio, USA ![]() |
10 | ![]() | I100929 | b. 24 Oct 1903 | Wheeling, Ohio County, West Virginia, USA ![]() |