Search Results
Matches 1 to 7 of 7 for First Name contains RICHARD FRED AND Tree equals Suedpfalz
# | Last Name, Given Name(s) ![]() |
Person ID | Born/Christened ![]() |
Location |
---|---|---|---|---|
1 | ![]() | I13638 | b. 3 May 1925 | Indiana, USA ![]() |
2 | ![]() | I435708 | ||
3 | ![]() | I70542 | b. 12 Jun 1923 | Bellaire, Belmont County, Ohio, USA ![]() |
4 | ![]() | I477798 | b. 21 Aug 1919 | Delphos, Allen County, Ohio, USA ![]() |
5 | ![]() | I42155 | b. 3 Oct 1898 | Louisville, Jefferson County, Kentucky, USA ![]() |
6 | ![]() | I313454 | b. 19 Apr 1872 | Rochester, Monroe County, New York, USA ![]() |
7 | ![]() | I426479 | b. 31 Dec 1928 | Saskatchewan, Canada ![]() |